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(B) The pressure at depth $h$ is given by $\Delta P = h \rho g$. Bulk modulus $B$ is defined as $B = \frac{\Delta P}{\Delta V / V}$. Therefore,the fra

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$1.34 	imes 10^{-2}$

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(B) The pressure at depth $h$ is given by $\Delta P = h ho g$. Bulk modulus $B$ is defined as $B = \frac{\Delta P}{\Delta V / V}$. Therefore,the fractional compression is $\frac{\Delta V}{V} = \frac{\Delta P}{B} = \frac{h ho g}{B}$. Given: $h = 3000 \,m$,$ho = 1000 \,kg/m^3$,$g = 9.8 \,m/s^2$,and $B = 2.2 	imes 10^9 \,N/m^2$. Substituting these values: $\frac{\Delta V}{V} = \frac{3000 	imes 1000 	imes 9.8}{2.2 	imes 10^9} = \frac{2.94 	imes 10^7}{2.2 	imes 10^9} = 1.336 	imes 10^{-2} \approx 1.34 	imes 10^{-2}$.

The average depth of the Indian Ocean is about $3000 \,m$. The value of fractional compression $\left(\frac{\Delta V}{V}\right)$ of water at the bottom of the ocean is (given that the bulk modulus of water is $2.2 \times 10^9 \,N/m^2$,$g = 9.8 \,m/s^2$,$\rho_{H_2O} = 1000 \,kg/m^3$):

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