The coefficient of variation for the followin | vedclass

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(B) The mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{3(5) + 2(7) + 1(9) + 2(11)}{3+2+1+2} = \frac{15+14+9+22}{8} = \frac{60}{8} = 7.5$.The va

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$20 \frac{\sqrt{23}}{3}$

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(B) The mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i} = \frac{3(5) + 2(7) + 1(9) + 2(11)}{3+2+1+2} = \frac{15+14+9+22}{8} = \frac{60}{8} = 7.5$.The variance $\sigma^2 = \frac{\sum f_i x_i^2}{\sum f_i} - (\bar{x})^2 = \frac{3(25) + 2(49) + 1(81) + 2(121)}{8} - (7.5)^2 = \frac{75+98+81+242}{8} - 56.25 = \frac{496}{8} - 56.25 = 62 - 56.25 = 5.75$.Standard deviation $\sigma = \sqrt{5.75} = \sqrt{\frac{575}{100}} = \frac{\sqrt{23 	imes 25}}{10} = \frac{5\sqrt{23}}{10} = \frac{\sqrt{23}}{2}$.Coefficient of variation ($C$.$V$.) $= \frac{\sigma}{\bar{x}} 	imes 100 = \frac{\sqrt{23}/2}{7.5} 	imes 100 = \frac{\sqrt{23}}{15} 	imes 100 = \frac{20\sqrt{23}}{3}$.

$x_i$	$5$	$7$	$9$	$11$
$f_i$	$3$	$2$	$1$	$2$

The coefficient of variation for the following data is:
$x_i$ $5$ $7$ $9$ $11$
$f_i$ $3$ $2$ $1$ $2$

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The coefficient of variation for the following data is:$x_i$$5$$7$$9$$11$$f_i$$3$$2$$1$$2$