The common features among the species CN^{-}, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The species $CN^{-}$,$CO$,and $NO^{+}$ are isoelectronic,each containing $14$ electrons. According to Molecular Orbital Theory,the bond order $(B.

Vedclass · Accepted Answer

Bond order three and diamagnetic

Vedclass · Answer

(A) The species $CN^{-}$,$CO$,and $NO^{+}$ are isoelectronic,each containing $14$ electrons. According to Molecular Orbital Theory,the bond order $(B.O.)$ for these species is calculated as: $B.O. = \frac{1}{2} (N_b - N_a) = \frac{1}{2} (10 - 4) = 3$. Since all electrons are paired in their molecular orbitals,they are diamagnetic. Additionally,they all act as strong field ligands and $\pi-$acceptor ligands. Comparing the options,the most accurate description of their common features is that they have a bond order of $3$ and are diamagnetic. Species$B.O.$Total Electrons$CN^{-}$$3$$14$$CO$$3$$14$$NO^{+}$$3$$14$

The common features among the species $CN^{-}$,$CO$ and $NO^{+}$ are

Similar Questions

Find the odd-electron molecules from the following:
$(i) C_2, (ii) H_2, (iii) SCl_2, (iv) NO, (v) NO_2$

The sum of bond order values of $C_2$ and $O_2^{2+}$ is $x$,which is equal to the sum of bond order values of $a, b$ and $c$. What are $a, b$ and $c$?

How do you express the bond strength in terms of bond order?

The paramagnetic behaviour of $B_2$ is due to the presence of

The number of anti-bonding electrons present in $O_{2}^{-}$ molecular ion is

Vedclass Test Series

Exam Paper Generator

Online Exam Module