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Question

(C) Optical activity in coordination complexes requires the absence of a plane of symmetry or a center of inversion.$1$. $trans-[Fe(NH_3)_2(CN)_4]^-$

Vedclass · Accepted Answer

$cis-[CrCl_2(ox)_2]^{3-}$

Vedclass · Answer

(C) Optical activity in coordination complexes requires the absence of a plane of symmetry or a center of inversion.$1$. $trans-[Fe(NH_3)_2(CN)_4]^-$ has a plane of symmetry,so it is optically inactive.$2$. $cis-[Fe(NH_3)_2(CN)_4]^-$ also possesses a plane of symmetry,making it optically inactive.$3$. $cis-[CrCl_2(ox)_2]^{3-}$ lacks both a plane of symmetry and a center of inversion,therefore it is chiral and shows optical activity.$4$. $trans-[CrCl_2(ox)_2]^{3-}$ has a plane of symmetry,so it is optically inactive.Thus,the correct option is $C$.

The complex that can show optical activity is:

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