(B) The given equation of the parabola is $(x+3)^2 = 2(y-5)$.Comparing this with the standard form $(x-h)^2 = 4a(y-k)$,we get the vertex $(h, k) = (-3

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(B) The given equation of the parabola is $(x+3)^2 = 2(y-5)$.Comparing this with the standard form $(x-h)^2 = 4a(y-k)$,we get the vertex $(h, k) = (-3, 5)$.Here,$4a = 2$,which implies $a = 1/2$.The focus of a parabola of the form $(x-h)^2 = 4a(y-k)$ is given by $(h, k+a)$.Substituting the values,the focus is $(-3, 5 + 1/2) = (-3, 11/2)$.Thus,option $B$ is correct.

Class 11 Mathematics 10-2. Parabola, Ellipse, Hyperbola Parabola

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The coordinates of the focus of the parabola $(x+3)^2 = 2(y-5)$ are

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A
$(-5/2, 5)$
B
$(-3, 11/2)$
C
$(3, -11/2)$
D
$(0, 1/2)$

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10-2. Parabola, Ellipse, Hyperbola

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Parabola

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