The coordinates of the foot of the perpendicular from $(0,0)$ upon the line $x+y=2$ are

Suppose $A$ and $B$ are two points on the line $2x - y + 3 = 0$ and $P(1, 2)$ is a point such that $PA = PB$. Then,the mid-point of $AB$ is

Two straight lines are drawn through the point $(0, 2)$ such that the lengths of the perpendiculars from the point $(4, 4)$ to these lines are each equal to $2$ units. The equation of the line joining the feet of these perpendiculars is

$x-y=0$ and $\frac{x}{2}+\frac{y}{2}=1$ are respectively the perpendicular bisectors of the sides $AB$ and $AC$ of a triangle $ABC$. If the vertex is $A(2, 3)$,then the equation of the side $BC$ is

Let the mirror image of point $A(1, 4)$ in the line $y = x$ be point $B$; the mirror image of point $B$ in the line $y = -x$ be $C$; and the mirror image of $C$ in the $x$-axis be $D$. Then,the area of triangle $ABD$ is ............... $sq. \, units$.

The image of the point $(6, 5)$ in the line $x = 3$ is