The current gain of a transistor is 0.98. If | vedclass

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(A) Given, the current gain $\alpha = 0.98$ (since $\alpha < 1$, it refers to the common base configuration).For a common emitter configuration, the c

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$24.5$

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(A) Given, the current gain $\alpha = 0.98$ (since $\alpha For a common emitter configuration, the current gain $\beta$ is given by the formula:$\beta = \frac{\alpha}{1 - \alpha} = \frac{0.98}{1 - 0.98} = \frac{0.98}{0.02} = 49$.We know that the relationship between collector current change $\Delta I_C$ and base current change $\Delta I_B$ in a common emitter configuration is:$\beta = \frac{\Delta I_C}{\Delta I_B}$.Given $\Delta I_B = 0.5 \,mA$, we can calculate $\Delta I_C$ as:$\Delta I_C = \beta 	imes \Delta I_B = 49 	imes 0.5 \,mA = 24.5 \,mA$.

The current gain of a transistor is $0.98$. If the transistor is used in a common emitter arrangement, what would be the change in collector current corresponding to a change of $0.5 \,mA$ in the base current (in $\,mA$)?

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