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(A) The limit of resolution $d	heta$ is given by the formula $d	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength and $D$ is the diam

Vedclass · Accepted Answer

$1.2$

Vedclass · Answer

(A) The limit of resolution $d	heta$ is given by the formula $d	heta = \frac{1.22 \lambda}{D}$,where $\lambda$ is the wavelength and $D$ is the diameter of the aperture.Given: $\lambda = 555 \, nm = 555 	imes 10^{-9} \, m$ and $D = 2 \, mm = 2 	imes 10^{-3} \, m$.Substituting the values: $d	heta = \frac{1.22 	imes 555 	imes 10^{-9}}{2 	imes 10^{-3}} \, rad$.$d	heta = 3.3855 	imes 10^{-4} \, rad$.To convert radians to minutes,multiply by $\frac{180}{\pi}$ and then by $60$:$d	heta (min) = 3.3855 	imes 10^{-4} 	imes \frac{180}{3.14159} 	imes 60 \approx 1.16 \, min$.Rounding to the nearest option,we get $1.2 \, min$.

The diameter of the pupil of the human eye is about $2 \, mm$. The human eye is most sensitive to the wavelength of $555 \, nm$. The limit of resolution of the human eye is ....... $min$.

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