The disperse phase in colloidal iron (III) hy | vedclass

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(C) The iron $(III)$ hydroxide sol is positively charged,while the gold sol is negatively charged.$(A)$ According to the Hardy-Schulze rule,the coagul

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Mixing the sols has no effect

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(C) The iron $(III)$ hydroxide sol is positively charged,while the gold sol is negatively charged.$(A)$ According to the Hardy-Schulze rule,the coagulating power of an ion is directly proportional to its charge. For the negatively charged gold sol,the coagulating power of cations $(Mg^{2+} > Na^+)$ is significant. For the positively charged iron $(III)$ hydroxide sol,the coagulating power of anions $(SO_4^{2-} > Cl^-)$ is significant. Magnesium chloride contains $Mg^{2+}$ ions,which are effective for the gold sol,but not for the iron $(III)$ hydroxide sol. Thus,the statement is correct.$(B)$ Sodium sulphate $(Na_2SO_4)$ provides $Na^+$ ions (which coagulate the gold sol) and $SO_4^{2-}$ ions (which coagulate the iron $(III)$ hydroxide sol). Thus,the statement is correct.$(C)$ When two oppositely charged sols are mixed,they neutralize each other's charges,leading to mutual coagulation. Therefore,saying that mixing has no effect is incorrect.$(D)$ Electrophoresis involves the movement of charged colloidal particles under an electric field,which leads to their discharge and subsequent coagulation at the electrodes. Thus,the statement is correct.

The disperse phase in colloidal iron $(III)$ hydroxide and colloidal gold is positively and negatively charged,respectively. Which of the following statements is $NOT$ correct?

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