The displacement of an oscillating particle varies with time $t$ (in seconds) according to the equation $y (cm) = \sin \left[ \frac{\pi}{2} \left( \frac{t}{2} + \frac{1}{3} \right) \right]$. The maximum acceleration of the particle is approximately ..... $cm/s^2$.

  • A
    $5.21$
  • B
    $3.62$
  • C
    $1.81$
  • D
    $0.62$

Explore More

Similar Questions

$A$ particle is performing $S.H.M.$ starting from the extreme position. The graphical representation shows that between displacement and acceleration,there is a phase difference of:

$Assertion :$ In $SHM$,acceleration is always directed towards the mean position.
$Reason :$ In $SHM$,the body has to stop momentarily at the extreme position and move back to the mean position.

The average acceleration of a particle performing $SHM$ over one complete oscillation is:

Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below:
$A \ (mm \ s^{-2})$$16$$8$$0$$-8$$-16$
$x \ (mm)$$-4$$-2$$0$$2$$4$

The period of the motion is:

Difficult
View Solution

Acceleration of a particle,executing $SHM$,at its mean position is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo