The distance of the point $(-2, 4, -5)$ from the line $\frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6}$ is

  • A
    $\frac{\sqrt{37}}{10}$
  • B
    $\sqrt{\frac{37}{10}}$
  • C
    $\frac{37}{\sqrt{10}}$
  • D
    $\frac{37}{10}$

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