The domain of the function f(x) = sqrt{frac{x | vedclass

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(B) For the function to be defined, the expression under the square root must be non-negative: $\frac{x-7}{9-x} \ge 0$.Multiply both sides by $-1$ and

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$[7, 9)$

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(B) For the function to be defined, the expression under the square root must be non-negative: $\frac{x-7}{9-x} \ge 0$.Multiply both sides by $-1$ and reverse the inequality sign: $\frac{x-7}{x-9} \le 0$.The critical points are $x = 7$ and $x = 9$.Since the denominator cannot be zero, $x 
eq 9$.Testing the intervals $(-\infty, 7]$, $[7, 9)$, and $[9, \infty)$, the inequality $\frac{x-7}{x-9} \le 0$ holds for $x \in [7, 9)$.Thus, the domain is $[7, 9)$.

The domain of the function $f(x) = \sqrt{\frac{x-7}{9-x}}$ is

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