The Earth's magnetic field at a certain place | vedclass

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(C) The total magnetic field $B$ is related to its horizontal component $B_H$ and vertical component $B_V$ by the equation $B^2 = B_V^2 + B_H^2$.Given

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$	an^{-1} \left( \frac{4}{3} ight)$

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(C) The total magnetic field $B$ is related to its horizontal component $B_H$ and vertical component $B_V$ by the equation $B^2 = B_V^2 + B_H^2$.Given $B = 0.5 \ G$ and $B_H = 0.3 \ G$,we can find $B_V$:$B_V = \sqrt{B^2 - B_H^2} = \sqrt{(0.5)^2 - (0.3)^2} = \sqrt{0.25 - 0.09} = \sqrt{0.16} = 0.4 \ G$.The angle of dip $\phi$ is given by the relation $	an \phi = \frac{B_V}{B_H}$.Substituting the values,$	an \phi = \frac{0.4}{0.3} = \frac{4}{3}$.Therefore,$\phi = 	an^{-1} \left( \frac{4}{3} ight)$.

The Earth's magnetic field at a certain place has a horizontal component of $0.3 \ G$ and the total strength of $0.5 \ G$. The angle of dip is:

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