The equation x^2 - 7xy + 12y^2 = 0 represents | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The given equation is $x^2 - 7xy + 12y^2 = 0$. Factorizing the quadratic expression: $x^2 - 3xy - 4xy + 12y^2 = 0$. $x(x - 3y) - 4y(x - 3y) = 0$.

Vedclass · Accepted Answer

Pair of non-perpendicular intersecting straight lines

Vedclass · Answer

(D) The given equation is $x^2 - 7xy + 12y^2 = 0$. Factorizing the quadratic expression: $x^2 - 3xy - 4xy + 12y^2 = 0$. $x(x - 3y) - 4y(x - 3y) = 0$. $(x - 3y)(x - 4y) = 0$. This represents two straight lines $x - 3y = 0$ and $x - 4y = 0$ passing through the origin. Since the slopes are $m_1 = 1/3$ and $m_2 = 1/4$,and $m_1 	imes m_2 
eq -1$,the lines are non-perpendicular and intersect at the origin. Therefore,the correct option is $D$.

The equation $x^2 - 7xy + 12y^2 = 0$ represents

Similar Questions

If the products of the perpendiculars from the origin to the pairs of lines $xy+x+y+1=0$,$x^2-y^2+2x+1=0$,and $2x^2+3xy-2y^2+2x+1=0$ are $p_1, p_2$,and $p_3$ respectively,then:

If one of the lines represented by the equation $ax^2 + 2hxy + by^2 = 0$ bisects the angle between the coordinate axes in the first quadrant,then which of the following is true?

The joint equation of the straight lines $x + y = 1$ and $x - y = 4$ is

The value of $k$,if the slope of one of the lines given by $4x^2 + kxy + y^2 = 0$ is four times that of the other,is given by

The equation $8 x^2-24 x y+18 y^2-6 x+9 y-5=0$ represents a

Vedclass Test Series

Exam Paper Generator

Online Exam Module