The equation axy + byz = cy represents the lo | vedclass

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Question

(A) Given the equation $axy + byz = cy$. Rearranging the terms,we get $y(ax + bz - c) = 0$. This equation is satisfied if either $y = 0$ or $ax + bz -

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$zx$-plane or on the planes perpendicular to $zx$-plane

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(A) Given the equation $axy + byz = cy$. Rearranging the terms,we get $y(ax + bz - c) = 0$. This equation is satisfied if either $y = 0$ or $ax + bz - c = 0$. The equation $y = 0$ represents the $zx$-plane. The equation $ax + bz - c = 0$ represents a plane. Since the normal vector to this plane is $(a, 0, b)$,which is perpendicular to the $y$-axis,the plane is perpendicular to the $zx$-plane. Therefore,the locus consists of the $zx$-plane and a plane perpendicular to the $zx$-plane.

The equation $axy + byz = cy$ represents the locus of the points which lie on

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