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(D) The standard equation of a simple harmonic wave is given by $y = A \sin(\omega t - kx)$.Comparing the given equation $y = 5 \sin \frac{\pi}{2}(100

Vedclass · Accepted Answer

$25$

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(D) The standard equation of a simple harmonic wave is given by $y = A \sin(\omega t - kx)$.Comparing the given equation $y = 5 \sin \frac{\pi}{2}(100t - x)$ with the standard form:$y = 5 \sin(50\pi t - \frac{\pi}{2}x)$.Here,the angular frequency $\omega = 50\pi \ rad/s$.We know that the time period $T$ is related to angular frequency by the formula $T = \frac{2\pi}{\omega}$.Substituting the value of $\omega$:$T = \frac{2\pi}{50\pi} = \frac{1}{25} \ s$.$T = 0.04 \ s$.Therefore,the correct option is $D$.

The equation of a simple harmonic wave is given as $y = 5 \sin \frac{\pi}{2}(100t - x)$,where $x$ and $y$ are in meters and time $t$ is in seconds. The period of the wave is: (in $s$)

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