The equation of one of the lines represented | vedclass

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Question

(A) Given equation: $pq(x^2 - y^2) + (p^2 - q^2)xy = 0$Expanding the terms: $pqx^2 - pqy^2 + p^2xy - q^2xy = 0$Rearranging the terms: $pqx^2 + p^2xy -

Vedclass · Accepted Answer

$px - qy = 0$

Vedclass · Answer

(A) Given equation: $pq(x^2 - y^2) + (p^2 - q^2)xy = 0$Expanding the terms: $pqx^2 - pqy^2 + p^2xy - q^2xy = 0$Rearranging the terms: $pqx^2 + p^2xy - q^2xy - pqy^2 = 0$Grouping the terms: $px(qx + py) - qy(qx + py) = 0$Factoring out the common term: $(qx + py)(px - qy) = 0$Thus,the two lines are $qx + py = 0$ and $px - qy = 0$.Comparing with the given options,the correct equation is $px - qy = 0$.

The equation of one of the lines represented by the equation $pq(x^2 - y^2) + (p^2 - q^2)xy = 0$ is

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