The expression $[(p \wedge \sim q) \vee q] \vee (\sim p \wedge q)$ is equivalent to

  • A
    $p \vee q$
  • B
    $p \wedge q$
  • C
    $p \rightarrow q$
  • D
    $p \leftrightarrow q$

Explore More

Similar Questions

$\sqrt[3]{61 - 46\sqrt{5}} = $

$A$ proton moves on a circular path with a constant angular speed. What is the correct relation between its magnetic moment $\vec M$ and angular momentum $\vec L$?

$A$ circular disc of radius $R$ is removed from a bigger circular disc of radius $2R$ such that the circumferences of the discs coincide. The center of mass of the new disc is $\alpha R$ from the center of the bigger disc. The value of $\alpha$ is:

The coefficient of performance of a refrigerator is $5$. If the temperature inside the freezer is $-20\,^{\circ}C$,the temperature of the surroundings to which it rejects heat is ....... $^{\circ}C$.

The angle between the lines joining the origin to the points of intersection of the line $x + 2y + 1 = 0$ and the curve $2x^2 - 2xy + 3y^2 + 2x - y - 1 = 0$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo