The focus of the parabola y^2 = 4y - 4x is | vedclass

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(A) Given equation: $y^2 = 4y - 4x$Rearranging the terms: $y^2 - 4y = -4x$Completing the square on the left side: $y^2 - 4y + 4 = -4x + 4$$(y - 2)^2 =

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$(0, 2)$

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(A) Given equation: $y^2 = 4y - 4x$Rearranging the terms: $y^2 - 4y = -4x$Completing the square on the left side: $y^2 - 4y + 4 = -4x + 4$$(y - 2)^2 = -4(x - 1)$Comparing this with the standard form $(y - k)^2 = -4a(x - h)$,where the vertex is $(h, k)$ and the focus is $(h - a, k)$:Here,$h = 1$,$k = 2$,and $4a = 4$,so $a = 1$.The focus is $(h - a, k) = (1 - 1, 2) = (0, 2)$.

The focus of the parabola $y^2 = 4y - 4x$ is

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