The following table gives the production yield per hectare of wheat of $100$ farms of a village.
Production yield (in kg/ha)Number of farms
$50-55$$2$
$55-60$$8$
$60-65$$12$
$65-70$$24$
$70-75$$38$
$75-80$$16$

Change the distribution to a 'more than type' distribution,and draw its ogive.

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(N/A) The cumulative frequency distribution of 'more than type' can be obtained as follows:
Production yield (lower class limits)Cumulative frequency
More than or equal to $50$$100$
More than or equal to $55$$100 - 2 = 98$
More than or equal to $60$$98 - 8 = 90$
More than or equal to $65$$90 - 12 = 78$
More than or equal to $70$$78 - 24 = 54$
More than or equal to $75$$54 - 38 = 16$

By plotting the points $(50, 100), (55, 98), (60, 90), (65, 78), (70, 54), (75, 16)$ on a graph paper,taking the lower class limits on the $x$-axis and their respective cumulative frequencies on the $y$-axis,we obtain the 'more than type' ogive.

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Similar Questions

The median of the following data is $525$. Find the values of $x$ and $y$,if the total frequency is $100$.
Class intervalFrequency
$0-100$$2$
$100-200$$5$
$200-300$$x$
$300-400$$12$
$400-500$$17$
$500-600$$20$
$600-700$$y$
$700-800$$9$
$800-900$$7$
$900-1000$$4$

The wickets taken by a bowler in $10$ cricket matches are as follows:
$2, 6, 4, 5, 0, 2, 1, 3, 2, 3$
Find the mode of the data.

The following table gives the literacy rate (in percentage) of $35$ cities. Find the mean literacy rate.
Literacy rate (in $\%$)$45-55$$55-65$$65-75$$75-85$$85-95$
Number of cities$3$$10$$11$$8$$3$

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The annual profits earned by $30$ shops of a shopping complex in a locality give rise to the following distribution:
Profit (Rs in lakhs)Number of shops (frequency)
More than or equal to $5$$30$
More than or equal to $10$$28$
More than or equal to $15$$16$
More than or equal to $20$$14$
More than or equal to $25$$10$
More than or equal to $30$$7$
More than or equal to $35$$3$

Draw both ogives for the data above. Hence,obtain the median profit.

$100$ surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Number of letters$1-4$$4-7$$7-10$$10-13$$13-16$$16-19$
Number of surnames$6$$30$$40$$16$$4$$4$

Determine the median number of letters in the surnames. Find the mean number of letters in the surnames. Also,find the modal size of the surnames.

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