The formulae of ammonium phosphomolybdate $(X)$ and the compound $(Y)$ responsible for Prussian blue colour are:

  • A
    $X: (NH_4)_3PO_4 \cdot 12MoO_3, Y: Fe_4[Fe(CN)_6]_3 \cdot xH_2O$
  • B
    $X: (NH_4)_3PO_3 \cdot 12MoO_3, Y: Fe_4[Fe(CN)_6]_3 \cdot xH_2O$
  • C
    $X: (NH_4)_2PO_3 \cdot 12MoO_3, Y: Fe_3[Fe(CN)_6]_2 \cdot xH_2O$
  • D
    $X: (NH_4)_3PO_4 \cdot 12MoO_3, Y: Fe_3[Fe(CN)_5]_2 \cdot xH_2O$

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Similar Questions

The volume of nitrogen is measured by which apparatus in the Dumas method?

Match the compounds in Column $I$ with their characteristic test$(s)$ reaction$(s)$ given in Column $II$.
Column $I$ Column $II$
$A. H_2N-NH_3^+Cl^-$ $p. \text{Sodium fusion extract of the compound gives Prussian blue colour with } FeSO_4$
$B. HO-C_6H_4-CH(NH_3^+)COOH \text{ (with } I^- \text{ counterion)}$ $q. \text{Gives positive } FeCl_3 \text{ test}$
$C. HO-C_6H_4-NH_3^+Cl^-$ $r. \text{Gives white precipitate with } AgNO_3$
$D. (NO_2)_2C_6H_3-NH-NH_3^+Br^-$ $s. \text{Reacts with aldehydes to form the corresponding hydrazone derivative}$

Identify the binary mixture$(s)$ that can be separated into individual compounds by differential extraction,as shown in the given scheme.
$(A)$ $C_6H_5OH$ and $C_6H_5COOH$
$(B)$ $C_6H_5COOH$ and $C_6H_5CH_2OH$
$(C)$ $C_6H_5CH_2OH$ and $C_6H_5OH$
$(D)$ $C_6H_5CH_2OH$ and $C_6H_5CH_2COOH$

The compound that does not give a positive test for nitrogen in Lassaigne's test is

Match the compounds in List-$I$ with the observations in List-$II$,and choose the correct option.
List-$I$ List-$II$
$I$. Aniline $P$. Sodium fusion extract of the compound on boiling with $FeSO_4$,followed by acidification with conc. $H_2SO_4$,gives Prussian blue color.
$II$. $o$-Cresol $Q$. Sodium fusion extract of the compound on treatment with sodium nitroprusside gives blood red color.
$III$. Cysteine $R$. Addition of the compound to a saturated solution of $NaHCO_3$ results in effervescence.
$IV$. Caprolactam $S$. The compound reacts with bromine water to give a white precipitate.
$T$. Treating the compound with neutral $FeCl_3$ solution produces violet color.

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