The frequency of the fourth overtone of a closed pipe is in unison with the fifth overtone of an open pipe. The ratio of the length of the closed pipe to that of the open pipe is

If the length of a closed organ pipe is $1 \ m$ and the velocity of sound is $330 \ m/s$,then the frequency for the second note (first overtone) is:

For air at room temperature, the atmospheric pressure is $1.0 \times 10^{5} \text{ Nm}^{-2}$ and the density of air is $1.2 \text{ kgm}^{-3}$. For a tube of length $1.0 \text{ m}$, closed at one end, the lowest frequency generated is $84 \text{ Hz}$. The value of $\gamma$ (ratio of two specific heats) for air is:

The frequency of the first overtone of a closed pipe of length $l_{1}$ is equal to that of the first overtone of an open pipe of length $l_{2}$. The ratio of their lengths $(l_{1}: l_{2})$ is

$A$ pipe with $30 \ cm$ length is open at both ends. Which harmonic mode of the pipe resonates with a $1.65 \ kHz$ source? (Velocity of sound in air $= 330 \ m/s$)

$A$ tube closed at one end and containing air is excited. It produces the fundamental note of frequency $512 \ Hz$. If the same tube is open at both ends,the fundamental frequency that can be produced is .... $Hz$.