The frequencies of tuning forks $A$ and $B$ are respectively $3\%$ more and $2\%$ less than the frequency of tuning fork $C$. When $A$ and $B$ are simultaneously excited,$5$ beats per second are produced. Then the frequency of the tuning fork $A$ (in $Hz$) is

The frequency of a tuning fork is $n \ Hz$ and the velocity of sound in air is $V \ m/s$. When the tuning fork completes $x$ vibrations,the distance traveled by the wave is:

$A$ tuning fork whose frequency as given by the manufacturer is $512 \ Hz$ is being tested with an accurate oscillator. It is found that the fork produces a beat of $2 \ Hz$ when the oscillator reads $514 \ Hz$,but produces a beat of $6 \ Hz$ when the oscillator reads $510 \ Hz$. The actual frequency of the fork is ..... $Hz$.

Three sound waves of equal amplitudes have frequencies $(f-1)$,$f$,and $(f+1)$. They superpose to produce beats. The number of beats produced per second will be:

$A$ source of frequency $\nu$ gives $6 \text{ beats/second}$ when sounded with a source of frequency $200 \text{ Hz}$. The second harmonic of frequency $2\nu$ of the source gives $8 \text{ beats/second}$ when sounded with a source of frequency $420 \text{ Hz}$. The value of $\nu$ is (in $text{ Hz}$)

Two harmonic waves moving in the same direction superimpose to form a wave $x = a \cos(1.5 t) \cos(50.5 t)$ where $t$ is in seconds. Find the period with which they beat (close to the nearest integer). (in $s$)