(A) Given function is $f(x) = x^{2} - 2x$. To find the interval where the function is strictly decreasing,we first find the derivative $f'(x)$. $f'(x)

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(A) Given function is $f(x) = x^{2} - 2x$. To find the interval where the function is strictly decreasing,we first find the derivative $f'(x)$. $f'(x) = \frac{d}{dx}(x^{2} - 2x) = 2x - 2$. $A$ function is strictly decreasing when $f'(x) So,$2x - 2 $2(x - 1) $x - 1 $x Thus,the function $f(x)$ is strictly decreasing in the interval $(-\infty, 1)$.

Class 12 Mathematics Applications of Derivatives Increasing and Decreasing function

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The function $f(x)=x^{2}-2x$ is strictly decreasing in the interval

KCET 2021 All KCET

A
$(-\infty, 1)$
B
$(1, \infty)$
C
$R$
D
$(-\infty, \infty)$

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Increasing and Decreasing function

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The function $f(x)=x^{2}-2x$ is strictly decreasing in the interval

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