The given electrical network is equivalent to

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(D) The circuit consists of a $NOR$ gate followed by another $NOR$ gate acting as a $NOT$ gate (both inputs tied together),followed by a $NOT$ gate. L

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$NOR$ gate

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(D) The circuit consists of a $NOR$ gate followed by another $NOR$ gate acting as a $NOT$ gate (both inputs tied together),followed by a $NOT$ gate. Let the output of the first $NOR$ gate be $C = \overline{A+B}$.This signal $C$ is fed into the second $NOR$ gate,which acts as a $NOT$ gate,producing $\overline{C} = \overline{\overline{A+B}} = A+B$.Finally,this signal is passed through a $NOT$ gate,giving the final output $Y = \overline{\overline{C}} = \overline{A+B}$.Thus,the circuit is equivalent to a $NOR$ gate.

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