The greatest possible number of points of int | vedclass

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(B) To find the maximum number of intersection points,we consider all possible pairs of intersections:$1$. Intersection of $8$ lines with each other:

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$104$

Vedclass · Answer

(B) To find the maximum number of intersection points,we consider all possible pairs of intersections:$1$. Intersection of $8$ lines with each other: The maximum number of points is given by $^8C_2 = \frac{8 	imes 7}{2} = 28$.$2$. Intersection of $4$ circles with each other: Each pair of circles intersects at $2$ points. The number of pairs is $^4C_2 = \frac{4 	imes 3}{2} = 6$. So,$6 	imes 2 = 12$ points.$3$. Intersection of $8$ lines with $4$ circles: Each line can intersect each circle at $2$ points. So,$8 	imes 4 	imes 2 = 64$ points.Total points = $28 + 12 + 64 = 104$.

The greatest possible number of points of intersection of $8$ distinct straight lines and $4$ distinct circles is

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