The height of a cylinder is decreased by 8 %, | vedclass

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(C) The volume $V$ of a cylinder is given by the formula $V = \pi r^2 h$,where $r$ is the radius and $h$ is the height.Since the radius $r$ remains un

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$8 \%$ decrease

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(C) The volume $V$ of a cylinder is given by the formula $V = \pi r^2 h$,where $r$ is the radius and $h$ is the height.Since the radius $r$ remains unchanged,the volume $V$ is directly proportional to the height $h$ $(V \propto h)$.If the height $h$ is decreased by $8 \%$,the new height $h'$ becomes $h' = h - 0.08h = 0.92h$.The new volume $V'$ will be $V' = \pi r^2 (0.92h) = 0.92 V$.The percentage change in volume is given by $\frac{V' - V}{V} 	imes 100 \%$.$= \frac{0.92V - V}{V} 	imes 100 \% = -0.08 	imes 100 \% = -8 \%$.The negative sign indicates a decrease.Therefore,the volume of the cylinder decreases by $8 \%$.

The height of a cylinder is decreased by $8 \%$,keeping its radius unchanged. What is the percentage change in its volume?

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