The kinetic energy of a body is increased by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The relationship between kinetic energy $K$ and momentum $p$ is given by $K = \frac{p^2}{2m}$,which implies $p = \sqrt{2mK}$.Let the initial kinet

Vedclass · Accepted Answer

increase twice

Vedclass · Answer

(A) The relationship between kinetic energy $K$ and momentum $p$ is given by $K = \frac{p^2}{2m}$,which implies $p = \sqrt{2mK}$.Let the initial kinetic energy be $K_1 = K$ and the final kinetic energy be $K_2 = 4K$.The initial momentum is $p_1 = \sqrt{2mK_1} = \sqrt{2mK}$.The final momentum is $p_2 = \sqrt{2mK_2} = \sqrt{2m(4K)} = 2\sqrt{2mK}$.Comparing the two,we get $p_2 = 2p_1$.Therefore,the momentum increases by $2$ times.

The kinetic energy of a body is increased by $4$ times. Its momentum will

Similar Questions

If a man increases his speed by $2 \, m/s$,his kinetic energy is doubled. The original speed of the man is:

What is the kinetic energy in Joules of a bullet of mass $2 \, g$ moving with a velocity of $500 \, m/s$ (in $, J$)?

If the kinetic energy $(K.E.)$ of a particle is doubled,then its momentum will

$A$ bullet of mass $50 \ g$ is fired with a speed $100 \ m/s$ on a plywood and emerges with $40 \ m/s$. The percentage loss of kinetic energy is:

If the velocity of an object of mass $300 \ g$ is $(3\hat{i} + 4\hat{j}) \ m/s$,then its kinetic energy is . . . . . . $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module