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(B) The initial magnetic moment is given by $M = m 	imes L$,where $m$ is the pole strength and $L$ is the length of the wire.When the wire is bent in

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$2M/\pi$

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(B) The initial magnetic moment is given by $M = m 	imes L$,where $m$ is the pole strength and $L$ is the length of the wire.When the wire is bent into a semicircle,the length $L$ becomes the arc length of the semicircle,so $L = \pi R$,where $R$ is the radius of the semicircle.Thus,$R = L / \pi$.The effective length (distance between the two poles) of the semicircle is the diameter,which is $2R$.The new magnetic moment $M_{	ext{new}}$ is given by $M_{	ext{new}} = m 	imes (2R)$.Substituting $R = L / \pi$,we get $M_{	ext{new}} = m 	imes 2 	imes (L / \pi) = (2 / \pi) 	imes (m 	imes L)$.Since $M = m 	imes L$,the new magnetic moment is $M_{	ext{new}} = 2M / \pi$.

The length of a steel wire is $L$ and its magnetic moment is $M$. On bending it into the shape of a semicircle,its magnetic moment will be

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