The length of one pair of opposite sides of a square is increased by $5 \, cm$ on each side,the ratio of the length and the breadth of the newly formed rectangle becomes $3:2$. What is the area of the original square? (in $cm^2$)
- A$25$
- B$81$
- C$100$
- D$225$
Explore More
Similar Questions
If the sides of a triangle are doubled,its area
Difficult
View SolutionIf the area of an equilateral triangle is equal to the area of an isosceles triangle whose base and equal sides are $16 \, cm$ and $10 \, cm$ respectively,then the side of the equilateral triangle is......$cm$
Medium
View SolutionThe area of a right-angled triangle with base $6\,m$ and hypotenuse $6.5\,m$ is........$m^2$
Medium
View SolutionThe total surface area of a rectangular block is $8788 \text{ cm}^2$. If the length,breadth,and height are in the ratio $4:3:2$,find the length (in $\text{cm}$).
Difficult
View SolutionThe length of a rectangular hall is $5\, m$ more than its breadth. The area of the hall is $750\, m^{2}$. The length of the hall is.........$m$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo