The load resistance and the base-emitter voltage of a transistor in $CE$ configuration are $5 \ k\Omega$ and $0.02 \ V$ respectively. If the collector current is $2 \ mA$,then its voltage gain is

Consider the circuit arrangement shown in figure $(1)$ for studying input and output characteristics of an $n-p-n$ transistor in $CE$ configuration. Select the values of $R_B$ and $R_C$ for a transistor whose $V_{BE} = 0.7 \, V$, so that the transistor is operating at point $Q$ as shown in the characteristics shown in figure $(2)$. Given that the input impedance of the transistor is very small and $V_{CC} = V_{BB} = 16 \, V$, also find the voltage gain and power gain of the circuit making appropriate assumptions.

$A$ transistor has a voltage gain '$A$'. If a fraction '$\beta$' of its output is fed back to the input of the transistor,then the transistor becomes an oscillator when:

In the given common-emitter circuit, an $npn$ transistor with $\beta = 100$ is connected. What is the output voltage of the amplifier?

The input resistance of a common emitter transistor amplifier,if the output resistance is $500\,k\Omega$,the current gain $\alpha = 0.98$ and power gain is $6.0625 \times 10^6$,is.......$\Omega$.

In a transistor (common emitter configuration) the ratio of power gain to voltage gain is ($\alpha$ and $\beta$ are current ratios)