The logic behind the NOR gate is that it give | vedclass

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(A) The $NOR$ gate is a combination of an $OR$ gate followed by a $NOT$ gate. The Boolean expression for an $OR$ gate is $Y = A + B$. The Boolean expr

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High output when both the inputs are low

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(A) The $NOR$ gate is a combination of an $OR$ gate followed by a $NOT$ gate. The Boolean expression for an $OR$ gate is $Y = A + B$. The Boolean expression for a $NOR$ gate is $Y = \overline{A + B}$. According to this expression, if both inputs $A$ and $B$ are $0$ (low), then $Y = \overline{0 + 0} = \overline{0} = 1$ (high). If any input is $1$ (high), the output becomes $0$ (low). Therefore, the $NOR$ gate gives a high output only when both inputs are low.

The logic behind the $NOR$ gate is that it gives

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