The magnetic potential energy stored in a cer | vedclass

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(C) The formula for magnetic potential energy $U$ stored in an inductor is given by $U = \frac{1}{2} L I^2$.Given:$U = 49 \ mJ = 49 	imes 10^{-3} \ J

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$20$

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(C) The formula for magnetic potential energy $U$ stored in an inductor is given by $U = \frac{1}{2} L I^2$.Given:$U = 49 \ mJ = 49 	imes 10^{-3} \ J$$I = 70 \ mA = 70 	imes 10^{-3} \ A = 7 	imes 10^{-2} \ A$Substituting the values into the formula:$49 	imes 10^{-3} = \frac{1}{2} 	imes L 	imes (7 	imes 10^{-2})^2$$49 	imes 10^{-3} = \frac{1}{2} 	imes L 	imes (49 	imes 10^{-4})$$49 	imes 10^{-3} = L 	imes (24.5 	imes 10^{-4})$$L = \frac{49 	imes 10^{-3}}{24.5 	imes 10^{-4}} = \frac{49}{24.5} 	imes 10^1 = 2 	imes 10 = 20 \ H$.

The magnetic potential energy stored in a certain inductor is $49 \ mJ$ when the current in the inductor is $70 \ mA$. The inductance of the inductor is (in $H$)

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