The major product in the reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reactant is benzene$-1,3-$dicarboxylic acid (isophthalic acid). Both $-COOH$ groups are strongly electron-withdrawing and meta-directing. In b

Vedclass · Accepted Answer

$1,3-$dicarboxy$-5-$bromobenzene

Vedclass · Answer

(B) The reactant is benzene$-1,3-$dicarboxylic acid (isophthalic acid). Both $-COOH$ groups are strongly electron-withdrawing and meta-directing. In benzene$-1,3-$dicarboxylic acid,the positions $2, 4, 5,$ and $6$ are available for electrophilic substitution. Position $5$ is meta to both $-COOH$ groups. Electrophilic aromatic substitution (bromination) occurs at the position that is meta to both electron-withdrawing groups to minimize steric hindrance and electronic repulsion. Therefore,the major product is $5$-bromobenzene-$1,3$-dicarboxylic acid.

Similar Questions

Identify the major product from the following reaction sequence:
$Cyclohexyl-CH_2CH_2OH \xrightarrow[(ii) Cl_2/Red \ P \ (iii) H_2O]{(i) CrO_3, H_2SO_4}$

What is $A$ in the following reaction?

Aspirin is an acetylation product of

Arrange the following in order of increasing reactivity (least $\to$ most) towards nucleophilic acyl substitution:
$1. CH_3COCH_2CH_3$,$2. CH_3COCl$,$3. CH_3CONHCH_3$

The carboxylic acid which has maximum solubility in water is

Vedclass Test Series

Exam Paper Generator

Online Exam Module