The median class of the following frequency d | vedclass

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(B) To find the median class,we first calculate the cumulative frequency $(cf)$ for each class:$1$. For class $0-10$,$cf = 4$.$2$. For class $10-20$,$

Vedclass · Accepted Answer

$30-40$

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(B) To find the median class,we first calculate the cumulative frequency $(cf)$ for each class:$1$. For class $0-10$,$cf = 4$.$2$. For class $10-20$,$cf = 4 + 5 = 9$.$3$. For class $20-30$,$cf = 9 + 9 = 18$.$4$. For class $30-40$,$cf = 18 + 10 = 28$.$5$. For class $40-50$,$cf = 28 + 14 = 42$.$6$. For class $50-60$,$cf = 42 + 8 = 50$.The total number of observations is $n = 50$.We need to find the class where the cumulative frequency is greater than or equal to $\frac{n}{2} = \frac{50}{2} = 25$.Looking at the cumulative frequencies: $4, 9, 18, 28, 42, 50$.The first cumulative frequency greater than $25$ is $28$,which corresponds to the class interval $30-40$.Therefore,the median class is $30-40$.

Class	$0-15$	$15-30$	$30-45$	$45-60$	$60-75$	$75-90$	$90-105$
Frequency	$4$	$5$	$23$	$45$	$66$	$42$	$15$

Class	$0-50$	$50-100$	$100-150$	$150-200$	$200-250$	$250-300$	$300-350$
Frequency	$10$	$15$	$30$	$20$	$15$	$8$	$2$

The median class of the following frequency distribution is ...........
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$
Frequency $4$ $5$ $9$ $10$ $14$ $8$

Total frequency $n = 50$.

Similar Questions

For a given frequency distribution,$A = 200$,$\Sigma f_{i} = 45$,$\Sigma f_{i} u_{i} = -216$ and $c = 10$. Then,mean $\bar{x} = \dots$

The formula $\ldots \ldots$ represents the empirical relationship between the measures of central tendency.

Find the mode of the following frequency distribution:

Class $0-15$ $15-30$ $30-45$ $45-60$ $60-75$ $75-90$ $90-105$

Frequency $4$ $5$ $23$ $45$ $66$ $42$ $15$

Find the mean,median and mode of the following frequency distribution:

Class $0-50$ $50-100$ $100-150$ $150-200$ $200-250$ $250-300$ $300-350$

Frequency $10$ $15$ $30$ $20$ $15$ $8$ $2$

For some given data,if $M + \bar{x} = 32$ and $M - \bar{x} = 2$,then $Z = \ldots \ldots \ldots$

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Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$4$	$5$	$9$	$10$	$14$	$8$

The median class of the following frequency distribution is ...........Class$0-10$$10-20$$20-30$$30-40$$40-50$$50-60$Frequency$4$$5$$9$$10$$14$$8$Total frequency $n = 50$.