The moment of inertia of a ring about an axis passing through the centre and perpendicular to its plane is $I$. It is rotating with angular velocity $\omega$. Another identical ring is gently placed on it so that their centres coincide. If both the rings are rotating about the same axis,then the loss in kinetic energy is

  • A
    $\frac{I \omega^2}{2}$
  • B
    $\frac{I \omega^2}{4}$
  • C
    $\frac{I \omega^2}{6}$
  • D
    $\frac{I \omega^2}{8}$

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