The most stable carbocation from the followin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the benzene ring.$1$. In $p$-methoxybenzyl c

Vedclass · Accepted Answer

Vedclass · Answer

(A) The stability of carbocations is determined by the electronic effects of the substituents attached to the benzene ring.$1$. In $p$-methoxybenzyl carbocation,the $-OCH_3$ group at the para position exerts a strong $+M$ (mesomeric) effect,which significantly stabilizes the positive charge through resonance.$2$. In $p$-methylbenzyl carbocation,the $-CH_3$ group provides stability through the $+H$ (hyperconjugation) effect.$3$. In $m$-methoxybenzyl carbocation,the $-OCH_3$ group exerts a $-I$ (inductive) effect because it is at the meta position,which destabilizes the carbocation.$4$. The benzyl carbocation has no additional substituents for stabilization.Therefore,the order of stability is: $p$-methoxybenzyl carbocation > $p$-methylbenzyl carbocation > benzyl carbocation > $m$-methoxybenzyl carbocation.The most stable carbocation is the $p$-methoxybenzyl carbocation.

The most stable carbocation from the following is:

Similar Questions

The lower stability of ethyl anion compared to methyl anion and the higher stability of ethyl radical compared to methyl radical,respectively,are due to

Consider the following carbocations:
$I. C_6H_5CH_2^+$
$II. CH_2=CH^+$
$III. CH_3-CH^+(CH_3)$
$IV. CH_3-CH_2^+$
$V. HC \equiv C^+$
Arrange the above carbocations in the order of decreasing stability.

$2-$chloropentane on halogenation with chlorine gives $2,3-$dichloropentane. What will be the structure of the free radical species formed in the reaction?

Which of the following is most likely to undergo a favorable hydride shift?

Which of the following is the most stable cation?

Vedclass Test Series

Exam Paper Generator

Online Exam Module