The negation of $(p \wedge \sim q) \rightarrow (p \vee \sim q)$ is

The negation of the statement "If a quadrilateral is a square,then it is a rhombus" is:

The proposition $(p$ $\Rightarrow \sim p) \wedge (\sim p$ $\Rightarrow p)$ is a

The number of values of $r \in \{p, q, \sim p, \sim q\}$ for which $((p \wedge q)$ $\Rightarrow (r \vee q)) \wedge ((p \wedge r)$ $\Rightarrow q)$ is a tautology,is:

If the truth value of the logical statement $(p \leftrightarrow \sim q) \rightarrow (\sim p \wedge q)$ is false,then the truth values of $p$ and $q$ are respectively:

The inverse of $p$ $\rightarrow (q$ $\rightarrow r)$ is logically equivalent to