The negation of the inverse of the statement | vedclass

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(B) Step $1$: Let the given statement be $S = \sim p \lor q$. The inverse of a conditional statement $p 	o q$ is $\sim p 	o \sim q$. However, the st

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$\sim p \land q$

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(B) Step $1$: Let the given statement be $S = \sim p \lor q$. The inverse of a conditional statement $p 	o q$ is $\sim p 	o \sim q$. However, the statement $\sim p \lor q$ is equivalent to $p 	o q$.Step $2$: The inverse of $p 	o q$ is $\sim p 	o \sim q$, which is equivalent to $\sim(\sim p) \lor \sim q = p \lor \sim q$.Step $3$: The negation of the inverse is $\sim(p \lor \sim q)$.Step $4$: By De Morgan's Law, $\sim(p \lor \sim q) = \sim p \land \sim(\sim q) = \sim p \land q$.

The negation of the inverse of the statement $\sim p \lor q$ is...

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