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In the compound $^1CH_2 = ^2CH - ^3CH_2 - ^4CH_2 - ^5C \equiv ^6CH$, the $C_2 - C_3$ bond is of which type?

Determine the hybridization of the carbon atoms in the following compounds:
$(a)$ $N \equiv C-CH=CH_2$
$(b)$ $HC \equiv C-CH=CH_2$ (Identify the carbon atoms of the single bond $C-C$)
$(c)$ $HC \equiv C-C \equiv CH$
$(d)$ $H_2C=C=C=CH_2$
$(e)$ Buta$-1,3-$diene (as shown in the figure)

What are the hybridisation states of each carbon atom in the following compounds?
$CH_2=C=O, \quad CH_3-CH=CH_2, \quad (CH_3)_2CO, \quad CH_2=CH-CN, \quad C_6H_6$

Which of the following bonds is most acidic?

What hybrid orbitals are present in the following compound $H_3C - CH = CH - CH_2 - CH_3$?

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