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(B) square matrix of order $5$ where each row sum is $1$ and each column sum is $1$ with entries from $\{0, 1\}$ is a permutation matrix.In the first

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$120$

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(B) square matrix of order $5$ where each row sum is $1$ and each column sum is $1$ with entries from $\{0, 1\}$ is a permutation matrix.In the first row,there are $5$ possible positions to place the $1$.In the second row,there are $4$ remaining positions available to place the $1$ (since the column used in the first row cannot be used again).In the third row,there are $3$ remaining positions.In the fourth row,there are $2$ remaining positions.In the fifth row,there is only $1$ remaining position.Therefore,the total number of such matrices is $5 	imes 4 	imes 3 	imes 2 	imes 1 = 5! = 120$.

The number of square matrices of order $5$ with entries from the set $\{0, 1\}$,such that the sum of all the elements in each row is $1$ and the sum of all the elements in each column is also $1$,is

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