The number of ways in which 3 boys and 2 girl | vedclass

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(C) To ensure no two boys sit together,we use the gap method.First,arrange the $2$ girls in a row,which can be done in $2! = 2$ ways.This creates $3$

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(C) To ensure no two boys sit together,we use the gap method.First,arrange the $2$ girls in a row,which can be done in $2! = 2$ ways.This creates $3$ gaps (one before the first girl,one between the girls,and one after the second girl) as shown: $\_ G \_ G \_$.We need to place $3$ boys in these $3$ gaps. The number of ways to arrange $3$ boys in $3$ gaps is $3! = 6$ ways.Therefore,the total number of ways is $2! 	imes 3! = 2 	imes 6 = 12$.

The number of ways in which $3$ boys and $2$ girls can sit on a bench so that no two boys are adjacent is . . . . . .

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