Easy
The order of filling of electrons in orbitals in $Ti$ is
- A$1 s, 2 s, 2 p, 3 s, 3 p, 3 d$ and $4 s$
- B$1 s, 2 s, 2 p, 3 s, 3 p, 4 s$ and $3 d$
- C$1 s, 2 s, 2 p, 3 s, 4 s, 3 p$ and $3 d$
- D$1 s, 2 s, 2 p, 3 s, 3 d, 3 p$ and $4 s$
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Similar Questions
Using $s$,$p$,$d$,and $f$ notations,describe the orbital with the following quantum numbers:
$(a)$ $n=1$,$l=0$
$(b)$ $n=3$,$l=1$
$(c)$ $n=4$,$l=2$
$(d)$ $n=4$,$l=3$
$(a)$ $n=1$,$l=0$
$(b)$ $n=3$,$l=1$
$(c)$ $n=4$,$l=2$
$(d)$ $n=4$,$l=3$
Medium
View SolutionWhich element is represented by the following electronic configuration?
Easy
View SolutionIf an atom has $13$ electrons in the $M$ shell and $1$ electron in the $N$ shell,then the number of unpaired electrons in that atom is ...
Medium
View SolutionThe electronic configuration of three elements $A$,$B$,and $C$ are given below. Stable form of $A$ may be represented by the formula:
$A : 1s^2, 2s^2, 2p^6$
$B : 1s^2, 2s^2, 2p^6, 3s^2, 3p^3$
$C : 1s^2, 2s^2, 2p^6, 3s^2, 3p^5$
$A : 1s^2, 2s^2, 2p^6$
$B : 1s^2, 2s^2, 2p^6, 3s^2, 3p^3$
$C : 1s^2, 2s^2, 2p^6, 3s^2, 3p^5$
Medium
View SolutionThe four quantum numbers for the valence shell electron of Sodium $(Z=11)$ are:
Easy
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