The p.m.f. of a random variable $X$ is $P(x) = \begin{cases} \frac{2x}{n(n+1)}, & x = 1, 2, 3, \ldots, n \\ 0, & \text{otherwise} \end{cases}$,then $E(X)$ is

  • A
    $\frac{n+1}{6}$
  • B
    $\frac{2n+1}{6}$
  • C
    $\frac{n+1}{3}$
  • D
    $\frac{2n+1}{3}$

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