The point of intersection of the line $\frac{x - 1}{3} = \frac{y + 2}{4} = \frac{z - 3}{-2}$ and the plane $2x - y + 3z - 1 = 0$ is

  • A
    $(10, -10, 3)$
  • B
    $(10, 10, -3)$
  • C
    $(-10, 10, 3)$
  • D
    None of these

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