The points on the parabola y^2 = 12x whose fo | vedclass

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(B) For a parabola $y^2 = 4ax$,the focal distance of a point $(x, y)$ is given by $x + a$.Given $y^2 = 12x$,we have $4a = 12$,so $a = 3$.The focal dis

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$(1, 2\sqrt{3}), (1, -2\sqrt{3})$

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(B) For a parabola $y^2 = 4ax$,the focal distance of a point $(x, y)$ is given by $x + a$.Given $y^2 = 12x$,we have $4a = 12$,so $a = 3$.The focal distance is $x + a = 4$.Substituting $a = 3$,we get $x + 3 = 4$,which implies $x = 1$.Substituting $x = 1$ into the equation $y^2 = 12x$,we get $y^2 = 12(1) = 12$.Thus,$y = \pm \sqrt{12} = \pm 2\sqrt{3}$.Therefore,the points are $(1, 2\sqrt{3})$ and $(1, -2\sqrt{3})$.

The points on the parabola $y^2 = 12x$ whose focal distance is $4$ are

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