(B) The potential energy $U$ of a system of two point charges $q_1$ and $q_2$ separated by a distance $r$ is given by the formula: $U = \frac{k q_1 q_

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(B) The potential energy $U$ of a system of two point charges $q_1$ and $q_2$ separated by a distance $r$ is given by the formula: $U = \frac{k q_1 q_2}{r}$.Given:$q_1 = q_2 = -2 \mu C = -2 \times 10^{-6} \text{ C}$$r = 1 \text{ m}$$k = 9 \times 10^9 \text{ N m}^2/\text{C}^2$Substituting the values into the formula:$U = \frac{(9 \times 10^9) \times (-2 \times 10^{-6}) \times (-2 \times 10^{-6})}{1}$$U = 9 \times 10^9 \times 4 \times 10^{-12}$$U = 36 \times 10^{-3} \text{ J}$$U = 3.6 \times 10^{-2} \text{ J}$.

Class 12 Physics Electric Potential and Capacitance Electric potential and Potential Energy of dipole

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The potential energy of a system of two equal negative point charges of $2 \mu C$ each,held $1 \ m$ apart in air,is . . . . . . . $\left( k = 9 \times 10^9 \text{ SI units} \right)$

GUJCET 2009 All GUJCET

A
$3.6 \times 10^{-3} \text{ J}$
B
$3.6 \times 10^{-2} \text{ J}$
C
$36 \text{ J}$
D
$3.6 \text{ J}$

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Electric Potential and Capacitance

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Electric potential and Potential Energy of dipole

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The potential energy of a system of two equal negative point charges of $2 \mu C$ each,held $1 \ m$ apart in air,is . . . . . . . $\left( k = 9 \times 10^9 \text{ SI units} \right)$

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