The electric potential at a point on the axis | vedclass

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Question

(B) The electric potential $V$ due to an electric dipole at a point at a distance $r$ from the center of the dipole is given by the formula $V = \frac

Vedclass · Accepted Answer

$ \propto \frac{1}{r^2} $

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(B) The electric potential $V$ due to an electric dipole at a point at a distance $r$ from the center of the dipole is given by the formula $V = \frac{1}{4\pi\epsilon_0} \frac{p \cos 	heta}{r^2}$,where $p$ is the dipole moment and $	heta$ is the angle between the dipole moment vector and the position vector of the point.For a point on the axis of the dipole,$	heta = 0^\circ$ or $180^\circ$,so $\cos 	heta = \pm 1$.Thus,the potential becomes $V = \pm \frac{1}{4\pi\epsilon_0} \frac{p}{r^2}$.From this expression,it is clear that $V \propto \frac{1}{r^2}$.

The electric potential at a point on the axis of an electric dipole depends on the distance $r$ of the point from the dipole as

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