The product formed from the following reactio | vedclass

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Question

(A) Step $1$: Aniline reacts with acetic anhydride $(CH_3CO)_2O$ in the presence of pyridine to form acetanilide $(C_6H_5NHCOCH_3)$.Step $2$: Acetanil

Vedclass · Accepted Answer

$N$-ethylaniline

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(A) Step $1$: Aniline reacts with acetic anhydride $(CH_3CO)_2O$ in the presence of pyridine to form acetanilide $(C_6H_5NHCOCH_3)$.Step $2$: Acetanilide is then reduced by $LiAlH_4$ (a strong reducing agent) which reduces the amide group $(-NHCOCH_3)$ to an amine group $(-NHCH_2CH_3)$.Step $3$: Hydrolysis $(H_2O)$ yields the final product,$N$-ethylaniline $(C_6H_5NHCH_2CH_3)$.

The product formed from the following reaction sequence is:

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Explain: Acetylation.

The decreasing order of basicity of the following amines is:
$(I)$ Aniline
$(II)$ Pyridine
$(III)$ Cyclohexylamine
$(IV)$ Pyrrole

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