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(D) Given,radius $r = \frac{h}{2}$,which implies $h = 2r$.The curved surface area of the cylinder is $A = 2 \pi r h = 616 \, cm^{2}$.Substituting $h =

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$2.2$

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(D) Given,radius $r = \frac{h}{2}$,which implies $h = 2r$.The curved surface area of the cylinder is $A = 2 \pi r h = 616 \, cm^{2}$.Substituting $h = 2r$ into the area formula: $2 \pi r (2r) = 616$.$4 \pi r^{2} = 616$.$r^{2} = \frac{616}{4 \pi} = \frac{154}{\frac{22}{7}} = \frac{154 	imes 7}{22} = 7 	imes 7 = 49$.Therefore,$r = 7 \, cm$ and $h = 2 	imes 7 = 14 \, cm$.The volume of the cylinder is $V = \pi r^{2} h = \frac{22}{7} 	imes (7)^{2} 	imes 14$.$V = 22 	imes 7 	imes 14 = 2156 \, cm^{3}$.Since $1000 \, cm^{3} = 1 \, 	ext{litre}$,the volume in litres is $\frac{2156}{1000} = 2.156 \, 	ext{litres}$.Rounding to one decimal place,we get approximately $2.2 \, 	ext{litres}$.

The radius of a cylinder is half its height and the curved surface area is $616 \, cm^{2}$. Approximately how many litres of milk can it contain?

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